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TEST PAPER-DE-11/8/2015 ____ 3rd CE

[Q.1 to 15 : 1 Marks and Q.16 to 20 : 2 Marks each.]

  1. (10101101.0111)2= (…?…)8
  2. (125.62)8= (…?…)2
  3. (1101101110.1001101)2= (…?..)16
  4. (8A9.B4)16= (…?…)2
  5. (615.25)8= (…?…)16
  6. (BC66.AF)16= (…?…)8
  7. (3102.12)4= (..?..)10
  8. Determine x, if: (193)x= (623)8
  9. (5386.345)10= (…?…)16
  10. (4433214)5= (…?…)12
  11. Perform (28)10­ – (15)10 using 6 bit 1’s com.
  12. Perform (15)10 – (28)10 using 6 bit 2’s com.
  13. Use 2’s complement : (a) 11010-1101 (b) 10010-10011
  14. Add (167)8 and (325)8
  15. Perform (46)10 – (22)10 in BCD using 9’s com.
  16. Write and Prove D’morgan Rule
  17. Simplify : A’B +A’BC’ +A’BCD+A’BC’D’E
  18. Simplify : (P+Q+R )( P’+Q’+R’)P
  19. Prove that :(((AB ̅+ABC)^’+A(B+AB ̅ )) ) ̅=0
  20. AB’C+A’BC+ABC = AC+BC
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